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</font></p><p align="left" style="margin: 0cm 0cm 0pt; text-align: left; line-height: normal;"><font color="#000000"><font face="맑은 고딕"><b style="mso-bidi-font-weight: normal;"><span style='font-size: 13pt; mso-fareast-font-family: "맑은 고딕"; mso-ascii-font-family: "맑은 고딕"; mso-ascii-theme-font: major-latin; mso-fareast-theme-font: major-latin; mso-hansi-font-family: "맑은 고딕"; mso-hansi-theme-font: major-latin;'>R[Ω]</span></b><b style="mso-bidi-font-weight: normal;"><span style='font-size: 13pt; mso-fareast-font-family: "맑은 고딕"; mso-ascii-font-family: "맑은 고딕"; mso-ascii-theme-font: major-latin; mso-fareast-theme-font: major-latin; mso-hansi-font-family: "맑은 고딕"; mso-hansi-theme-font: major-latin;'>의 동일한 저항<span > n</span>개를 직렬연결 시 합성저항 값은 병렬연결 시 <span ></span></span></b></font></font></p><p><font color="#000000" face="굴림" size="3">
</font></p><p align="left" style="margin: 0cm 0cm 10pt; text-align: left; line-height: normal; text-indent: 13pt; mso-char-indent-count: 1.0;"><span style='font-size: 13pt; mso-fareast-font-family: "맑은 고딕"; mso-ascii-font-family: "맑은 고딕"; mso-ascii-theme-font: major-latin; mso-fareast-theme-font: major-latin; mso-hansi-font-family: "맑은 고딕"; mso-hansi-theme-font: major-latin;'><font color="#000000"><font face="맑은 고딕"><strong>합성 저항 값의 몇 배인가</strong><span ><strong>? </strong>④</span></font></font></span></p><p align="left" style="margin: 0cm 0cm 10pt; text-align: left; line-height: normal; text-indent: 13pt; mso-char-indent-count: 1.0;"><span style='font-size: 13pt; mso-fareast-font-family: "맑은 고딕"; mso-ascii-font-family: "맑은 고딕"; mso-ascii-theme-font: major-latin; mso-fareast-theme-font: major-latin; mso-hansi-font-family: "맑은 고딕"; mso-hansi-theme-font: major-latin;'><font color="#000000"><font face="맑은 고딕"><span ></span></font></font></span><font color="#000000"><font face="맑은 고딕"><span style='font-size: 13pt; mso-fareast-font-family: "맑은 고딕"; mso-ascii-font-family: "맑은 고딕"; mso-ascii-theme-font: major-latin; mso-fareast-theme-font: major-latin; mso-hansi-font-family: "맑은 고딕"; mso-hansi-theme-font: major-latin;'>① </span><!--[if gte msEquation 12]><m:oMath><m:f><m:fPr><span
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</span><b style="mso-bidi-font-weight: normal;">n</b><span style="mso-spacerun: yes;"> </span><span style="mso-spacerun: yes;"> </span><span style="mso-spacerun: yes;"> </span>④<span style="mso-spacerun: yes;"> </span><b style="mso-bidi-font-weight: normal;">n²</b></span></font></font></p><p><font color="#000000" face="굴림" size="3">
</font></p><p><font color="#000000" face="굴림" size="3">
</font></p><p align="left" style="margin: 0cm 0cm 0pt; text-align: left; line-height: normal;"><font color="#000000"><font face="맑은 고딕"><span style='font-size: 13pt; mso-fareast-font-family: "맑은 고딕"; mso-ascii-font-family: "맑은 고딕"; mso-ascii-theme-font: major-latin; mso-fareast-theme-font: major-latin; mso-hansi-font-family: "맑은 고딕"; mso-hansi-theme-font: major-latin;'><span style="mso-spacerun: yes;"> </span>(만약에</span><span style='font-size: 13pt; mso-fareast-font-family: "맑은 고딕"; mso-ascii-font-family: "맑은 고딕"; mso-ascii-theme-font: major-latin; mso-fareast-theme-font: major-latin; mso-hansi-font-family: "맑은 고딕"; mso-hansi-theme-font: major-latin;'><span >) R1=3[Ω], R2=6[Ω]</span>의 직<span >/</span>병렬 합성저항은 </span></font></font></p><p align="left" style="margin: 0cm 0cm 0pt; text-align: left; line-height: normal;"><font color="#000000"><font face="맑은 고딕"><span style='font-size: 13pt; mso-fareast-font-family: "맑은 고딕"; mso-ascii-font-family: "맑은 고딕"; mso-ascii-theme-font: major-latin; mso-fareast-theme-font: major-latin; mso-hansi-font-family: "맑은 고딕"; mso-hansi-theme-font: major-latin;'> 직렬은 <span >3+6=9</span></span></font></font></p><p><font color="#000000" face="굴림" size="3">
</font><font color="#000000"><font face="맑은 고딕"><span style='font-size: 13pt; mso-fareast-font-family: "맑은 고딕"; mso-ascii-font-family: "맑은 고딕"; mso-ascii-theme-font: major-latin; mso-fareast-theme-font: major-latin; mso-hansi-font-family: "맑은 고딕"; mso-hansi-theme-font: major-latin;'><span style="mso-spacerun: yes;"> </span></span><span style='font-size: 13pt; mso-fareast-font-family: "맑은 고딕"; mso-ascii-font-family: "맑은 고딕"; mso-ascii-theme-font: major-latin; mso-fareast-theme-font: major-latin; mso-hansi-font-family: "맑은 고딕"; mso-hansi-theme-font: major-latin;'>병렬은<span > 3+6=9, 3*6=18 </span>이므로<span > 18 / 9 = 2 </span></span></font></font></p><p><font color="#000000"><font face="맑은 고딕"><span style='font-size: 13pt; mso-fareast-font-family: "맑은 고딕"; mso-ascii-font-family: "맑은 고딕"; mso-ascii-theme-font: major-latin; mso-fareast-theme-font: major-latin; mso-hansi-font-family: "맑은 고딕"; mso-hansi-theme-font: major-latin;'><span > </span>하여<span > n² </span>이다기 맞는 풀이 입니까?</span></font></font></p><p><font color="#000000" face="굴림" size="3">
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카페 게시글
Q&A게시판
R[Ω]의 동일한 저항 n개를 직렬연결 시 합성저항 값은 병렬연결 시 합성 저항 값의 몇 배인가?
사철나무
추천 0
조회 674
15.11.26 17:08
댓글 2
다음검색
첫댓글 동일한 저항입니다.. 3옴 6옴이 아니라 3옴이면 3옴 6옴이면 6옴으로 계산하셔야죠
3옴 3개면 직 nr=3×3= 9옴 병r/n = 3/3 1옴
Nr / r/n = n^2
감사합니다