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<p><span style="font-size: 12pt;"><strong><span style="font-family: Gulim,굴림,AppleGothic,sans-serif;">[회로이론 교재 p21, 문제4 관련]</span></strong></span></p><p><span style="font-size: 12pt;"><strong><span style="font-family: Gulim,굴림,AppleGothic,sans-serif;">예전에 </span></strong></span></p><p><span style="font-size: 12pt;"><strong><span style="font-family: Gulim,굴림,AppleGothic,sans-serif;">sin(90-x) = cosx</span></strong></span></p><p><span style="font-size: 12pt;"><strong><span style="font-family: Gulim,굴림,AppleGothic,sans-serif;">cos(90-x) = sinx</span></strong></span></p><p><span style="font-size: 12pt;"><strong><span style="font-family: Gulim,굴림,AppleGothic,sans-serif;">라고 배웠습니다.</span></strong></span></p><p><span style="font-size: 12pt;"><strong><span style="font-family: Gulim,굴림,AppleGothic,sans-serif;">이 공식을 문제4에 적용하면, </span></strong></span></p><p><span style="font-size: 12pt;"><strong><span style="font-family: Gulim,굴림,AppleGothic,sans-serif;">coswt = sin(90-wt)</span></strong></span></p><p><span style="font-size: 12pt;"><strong><span style="font-family: Gulim,굴림,AppleGothic,sans-serif;"> = sin[-(wt-90)]</span></strong></span></p><p><span style="font-size: 12pt;"><strong><span style="font-family: Gulim,굴림,AppleGothic,sans-serif;"> = -sin(wt-90)이 됩니다.</span></strong></span></p><p><strong><span style="font-family: Gulim,굴림,AppleGothic,sans-serif; font-size: 12pt;">이것은 교재 설명과 동일한 결과입니까?</span><span style="font-family: Gulim,굴림,AppleGothic,sans-serif; font-size: 12pt;"></span></strong></p><p><strong><span style="font-family: Gulim,굴림,AppleGothic,sans-serif; font-size: 12pt;"><br></span></strong></p><p><strong><span style="font-family: Gulim,굴림,AppleGothic,sans-serif; font-size: 12pt;"></span></strong><br></p>
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첫댓글 안녕하세요..답변드립니다.
sin (x+90) = cos x 이며
cos (x-90) = sin x 입니다.
sin(x+90) = cos(-x) = cosx
cos(x-90) = cos(90-x) = sinx