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Main Menu>Preprocessor>Loads>Define Loads>Delete>Structural>Inertia>Gravity |
Main Menu>Solution>Define Loads>Apply>Structural>Inertia>Gravity>Global |
+ 명령어 (lb)
MP,DENS,1,9345E-8 ! 단위 확인할것, 0.9345 x 10-4 lb-sec2/in4
ACEL,,,386.4 ! GRAVITY ! 단위확인할것. 386.4 in/sec2)
< Kgf=9.81Kgm m/sec^2 = 9.81N 이므로, Kgm=(1/9.81)Kgf sec^2/m. 즉,
Kgm/m^3 = (1/9.81)Kgf sec^2/m^4 임, 중량을 9.81로 나누면,사용할 density의 단위는 Kgf sec^2/m^4가 됨 >
+ 명령어 (kgf)
mp,ex,1,200000000000., ! Pa
mp,dens,1,7850., ! kg/m³
acel,,,9.80665 ! acel,x,y,z 방향 확인 할것
2. WB
첨부 참조 자중-워크밴치.ppt
하중적용에서 standard earth gravity !! 중력방향 그래프 확인할것.
vm158참조..예제
q. 물속에 들어 있는 플라스틱 실린더..가 물속에 어느정도 기게 잠기는지에 대한 문제?
Material Properties |
ρ = 8000 kg/m3 |
ρw = 1000 kg/m3 |
g = 9.807 m/sec2
///이하 로그 파일///
/VERIFY,VM158
/PREP7
MP,PRXY,,0.3
/TITLE, VM158, MOTION OF A BOBBING BUOY
C*** ELEMENTARY THEORETICAL FLUID MECHANICS, BRENKERT, PAGE 37
ANTYPE,TRANS
NLGEOM,ON ! LARGE DISPLACEMENTS
ET,1,PIPE59,,,,,,,1
R,1,1,.03 ! DIAMETER, WALL THICKNESS
RMORE,,,,.3 ! DRAG COEFFICIENT
MP,EX,1,21E10
MP,DENS,1,8000
MP,PRXY,1,0.3
TB,WATER,1
TBDATA,3,30 ! DEPTH
TBDATA,4,1000 ! WATER DENSITY
N,1,,,-9
N,7,,,1
FILL
E,1,2
EGEN,6,1,1
FINISH
/SOLU
NSUBST,20 ! 20 SUBSTEPS
CNVTOL,U ! CONVERGENCE BASED ON DISPLACEMENTS
CNVTOL,F ! CONVERGENCE BASED ON FORCES
OUTPR,BASIC,LAST
OUTRES,NSOL,1
KBC,1
ALPHAD,3 ! MASS DAMPING FOR SLOW DYNAMICS
ACEL,,,9.807
D,1,UX,,,7,,UY,ROTX,ROTY,ROTZ ! CONSTRAIN ALL BUT UZ DOF
TIME,30
SOLVE
FINISH
/POST26
NSOL,2,1,U,Z
PRVAR,2
/GRID,1
/AXLAB,Y,DISP
PLVAR,2