Re:삼각형과 사각형 중심의 자계세기 구하는 방법..

<a href="javascript:albumViewer('viewer','http://pds23.cafe.daum.net/download.php?grpid=6ddx&fldid=JA4N&dataid=682&fileid=1&regdt=20051009135553&disk=22&grpcode=physicslove&dncnt=N&.jpg')"><IMG hspace=0 src="https://img1.daumcdn.net/relay/cafe/original/?fname=http%3A%2F%2Fpds23.cafe.daum.net%2Fdownload.php%3Fgrpid%3D6ddx%26fldid%3DJA4N%26dataid%3D682%26fileid%3D1%26regdt%3D20051009135553%26disk%3D22%26grpcode%3Dphysicslove%26dncnt%3DN%26.jpg" width=751 align=absMiddle vspace=3 border=0 id=upload_image1 onload='controlImage(this.id);'></a>         <a href="javascript:albumViewer('viewer','http://pds23.cafe.daum.net/download.php?grpid=6ddx&fldid=JA4N&dataid=682&fileid=2&regdt=20051009135553&disk=5&grpcode=physicslove&dncnt=N&.jpg')"><IMG hspace=0 src="https://img1.daumcdn.net/relay/cafe/original/?fname=http%3A%2F%2Fpds23.cafe.daum.net%2Fdownload.php%3Fgrpid%3D6ddx%26fldid%3DJA4N%26dataid%3D682%26fileid%3D2%26regdt%3D20051009135553%26disk%3D5%26grpcode%3Dphysicslove%26dncnt%3DN%26.jpg" width=876 align=absMiddle vspace=3 border=0 id=upload_image2 onload='controlImage(this.id);'></a> <a href="javascript:albumViewer('viewer','http://pds23.cafe.daum.net/download.php?grpid=6ddx&fldid=JA4N&dataid=682&fileid=3&regdt=20051009135553&disk=9&grpcode=physicslove&dncnt=N&.jpg')"><IMG hspace=0 src="https://img1.daumcdn.net/relay/cafe/original/?fname=http%3A%2F%2Fpds23.cafe.daum.net%2Fdownload.php%3Fgrpid%3D6ddx%26fldid%3DJA4N%26dataid%3D682%26fileid%3D3%26regdt%3D20051009135553%26disk%3D9%26grpcode%3Dphysicslove%26dncnt%3DN%26.jpg" width=867 align=absMiddle vspace=3 border=0 id=upload_image3 onload='controlImage(this.id);'></a> <a href="javascript:albumViewer('viewer','http://pds23.cafe.daum.net/download.php?grpid=6ddx&fldid=JA4N&dataid=682&fileid=4&regdt=20051009135553&disk=5&grpcode=physicslove&dncnt=N&.jpg')"><IMG hspace=0 src="https://img1.daumcdn.net/relay/cafe/original/?fname=http%3A%2F%2Fpds23.cafe.daum.net%2Fdownload.php%3Fgrpid%3D6ddx%26fldid%3DJA4N%26dataid%3D682%26fileid%3D4%26regdt%3D20051009135553%26disk%3D5%26grpcode%3Dphysicslove%26dncnt%3DN%26.jpg" width=807 align=absMiddle vspace=3 border=0 id=upload_image4 onload='controlImage(this.id);'></a> <a href="javascript:albumViewer('viewer','http://pds23.cafe.daum.net/download.php?grpid=6ddx&fldid=JA4N&dataid=682&fileid=5&regdt=20051009135553&disk=19&grpcode=physicslove&dncnt=N&.jpg')"><IMG hspace=0 src="https://img1.daumcdn.net/relay/cafe/original/?fname=http%3A%2F%2Fpds23.cafe.daum.net%2Fdownload.php%3Fgrpid%3D6ddx%26fldid%3DJA4N%26dataid%3D682%26fileid%3D5%26regdt%3D20051009135553%26disk%3D19%26grpcode%3Dphysicslove%26dncnt%3DN%26.jpg" width=750 align=absMiddle vspace=3 border=0 id=upload_image5 onload='controlImage(this.id);'></a> <a href="javascript:albumViewer('viewer','http://pds23.cafe.daum.net/download.php?grpid=6ddx&fldid=JA4N&dataid=682&fileid=6&regdt=20051009135553&disk=28&grpcode=physicslove&dncnt=N&.jpg')"><IMG hspace=0 src="https://img1.daumcdn.net/relay/cafe/original/?fname=http%3A%2F%2Fpds23.cafe.daum.net%2Fdownload.php%3Fgrpid%3D6ddx%26fldid%3DJA4N%26dataid%3D682%26fileid%3D6%26regdt%3D20051009135553%26disk%3D28%26grpcode%3Dphysicslove%26dncnt%3DN%26.jpg" width=720 align=absMiddle vspace=3 border=0 id=upload_image6 onload='controlImage(this.id);'></a>   비오 사바르 법칙 (Biot-Savart law) 을 이용하여 자기장을 적분하면 풀수 있는 문제입니다.   비오 사바르 법칙이란 공간 상의 어떤 점에서의 자기장을 결정하는 법칙인데...   전류가 흐르면 주위에 자기장이 생깁니다. 그런데 일반적으로 도선의 모양은 완전 지 맘대로란 말이죠?   그래서 도선을 잘게 나누어서 미소 전류에 의한 자기장을 다 합치면, 그것이 바로 어떤 점에서의 자기장이 된다는 것입니다.   풀이를 못 적어드리는것이 안타까울 따름입니다 .1번 2번 문제는 유한한 길이를 가진 직선 도선에 의한 자기장을 적분하면 되고.. 3번은 원이니까 이것도 잘 적분을 ㄱ-;;아악