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<P>쉬운 문제인것 같은데요... 안풀리네요...</P>
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<P>일정량의 이상기체의 상태가 A에서 B로 변하였을 때 기체의 내부에너지 변화는?</P>
<P><!--StartFragment-->A는 압력 5, 부피 4 에서 B는 압력 10, 부피 8 로 부피와 압력과의 그래프에서 직선을 그립니다.<SPAN style="FONT-SIZE: 10pt; COLOR: #000000; LINE-HEIGHT: 16pt; FONT-FAMILY: '한컴바탕'; LETTER-SPACING: 0pt; TEXT-ALIGN: justify"> <!--StartFragment--> </SPAN><SPAN style="FONT-SIZE: 10pt; COLOR: #000000; LINE-HEIGHT: 16pt; FONT-FAMILY: '한컴바탕'; LETTER-SPACING: 0pt; TEXT-ALIGN: justify"></P>
<P style="FONT-SIZE: 10pt; MARGIN: 0pt; COLOR: #000000; TEXT-INDENT: 0pt; LINE-HEIGHT: 160%; FONT-FAMILY: '바탕'; TEXT-ALIGN: justify"><SPAN style="FONT-SIZE: 10pt; COLOR: #000000; LINE-HEIGHT: 16pt; FONT-FAMILY: '바탕'; LETTER-SPACING: 0pt; TEXT-ALIGN: justify">P (×10<A name=#757777e7></A>^6 N/m<A name=#757777e8></A>^2)</SPAN> <SPAN style="FONT-SIZE: 10pt; COLOR: #000000; LINE-HEIGHT: 16pt; FONT-FAMILY: '바탕'; LETTER-SPACING: 0pt; TEXT-ALIGN: justify">V(×10^-5 <A name=#757777e5></A> m^3<A name=#757777e6></A> )</SPAN></P>
<P style="FONT-SIZE: 10pt; MARGIN: 0pt; COLOR: #000000; TEXT-INDENT: 0pt; LINE-HEIGHT: 160%; FONT-FAMILY: '바탕'; TEXT-ALIGN: justify"><SPAN style="FONT-SIZE: 10pt; COLOR: #000000; LINE-HEIGHT: 16pt; FONT-FAMILY: '바탕'; LETTER-SPACING: 0pt; TEXT-ALIGN: justify"></SPAN> </P>
<P style="FONT-SIZE: 10pt; MARGIN: 0pt; COLOR: #000000; TEXT-INDENT: 0pt; LINE-HEIGHT: 160%; FONT-FAMILY: '바탕'; TEXT-ALIGN: justify"><SPAN style="FONT-SIZE: 10pt; COLOR: #000000; LINE-HEIGHT: 16pt; FONT-FAMILY: '바탕'; LETTER-SPACING: 0pt; TEXT-ALIGN: justify">답은 900J 이네요</SPAN></P>
<P style="FONT-SIZE: 10pt; MARGIN: 0pt; COLOR: #000000; TEXT-INDENT: 0pt; LINE-HEIGHT: 160%; FONT-FAMILY: '바탕'; TEXT-ALIGN: justify"><SPAN style="FONT-SIZE: 10pt; COLOR: #000000; LINE-HEIGHT: 16pt; FONT-FAMILY: '바탕'; LETTER-SPACING: 0pt; TEXT-ALIGN: justify">부탁드려요...</SPAN></P><SPAN style="FONT-SIZE: 10pt; COLOR: #000000; LINE-HEIGHT: 16pt; FONT-FAMILY: '바탕'; LETTER-SPACING: 0pt; TEXT-ALIGN: justify"></SPAN>
<P style="FONT-SIZE: 10pt; MARGIN: 0pt; COLOR: #000000; TEXT-INDENT: 0pt; LINE-HEIGHT: 160%; FONT-FAMILY: '바탕'; TEXT-ALIGN: justify"> </P>
<P style="FONT-SIZE: 10pt; MARGIN: 0pt; COLOR: #000000; TEXT-INDENT: 0pt; LINE-HEIGHT: 160%; FONT-FAMILY: '한컴바탕'; TEXT-ALIGN: justify"><SPAN style="FONT-SIZE: 10pt; COLOR: #000000; LINE-HEIGHT: 16pt; FONT-FAMILY: '한컴바탕'; LETTER-SPACING: 0pt; TEXT-ALIGN: justify"><A name=#757777f1></A></SPAN> </P>
<P style="FONT-SIZE: 10pt; MARGIN: 0pt; COLOR: #000000; TEXT-INDENT: 0pt; LINE-HEIGHT: 160%; FONT-FAMILY: '한컴바탕'; TEXT-ALIGN: justify"><BR></SPAN></P>
<P style="FONT-SIZE: 10pt; MARGIN: 0pt; COLOR: #000000; TEXT-INDENT: 0pt; LINE-HEIGHT: 160%; FONT-FAMILY: '한컴바탕'; TEXT-ALIGN: justify"><SPAN style="FONT-SIZE: 10pt; COLOR: #000000; LINE-HEIGHT: 16pt; FONT-FAMILY: '한컴바탕'; LETTER-SPACING: 0pt; TEXT-ALIGN: justify"> <!--StartFragment--> </P>
<P style="FONT-SIZE: 10pt; MARGIN: 0pt; COLOR: #000000; TEXT-INDENT: 0pt; LINE-HEIGHT: 160%; FONT-FAMILY: '바탕'; TEXT-ALIGN: justify"><SPAN style="FONT-SIZE: 10pt; COLOR: #000000; LINE-HEIGHT: 16pt; FONT-FAMILY: '바탕'; LETTER-SPACING: 0pt; TEXT-ALIGN: justify"><A name=#757777f1></A></SPAN></P>
<P style="FONT-SIZE: 10pt; MARGIN: 0pt; COLOR: #000000; TEXT-INDENT: 0pt; LINE-HEIGHT: 160%; FONT-FAMILY: '바탕'; TEXT-ALIGN: justify"> </P>
<P style="FONT-SIZE: 10pt; MARGIN: 0pt; COLOR: #000000; TEXT-INDENT: 0pt; LINE-HEIGHT: 160%; FONT-FAMILY: '한컴바탕'; TEXT-ALIGN: justify"><SPAN style="FONT-SIZE: 10pt; COLOR: #000000; LINE-HEIGHT: 16pt; FONT-FAMILY: '한컴바탕'; LETTER-SPACING: 0pt; TEXT-ALIGN: justify"><BR></SPAN></P>
<P style="FONT-SIZE: 10pt; MARGIN: 0pt; COLOR: #000000; TEXT-INDENT: 0pt; LINE-HEIGHT: 160%; FONT-FAMILY: '한컴바탕'; TEXT-ALIGN: justify"> <BR></SPAN></P>
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첫댓글 아마 단원자 이상기체인데 표시를 안해준듯하네요 자유도를 구할방도가 없어서요... 단원자 이상기체라면..△u=f/2 nR△T 이고 이상기체방정식으로 나중온도 T가 처음온도 t의 4배이니깐 온도차가 3t가 되어서 일단 △T를 구할 수있고. nR도 역시 PV=nRT공식에서 nR=PV/t 로 구할수있네요 처음 △U 식에 이수치넣구 자유도를 단원자 로 생각해서 f=3 을 넣으면 900J 나오네요 일단 참고하세요
그렇군요...고맙습니다^^